Two ships, a and b, leave port at the same time. ship a travels northwest at 21 knots and ship b travels at 25 knots in a direction 32° west of south. (1 knot = 1 nautical mile per hour; see appendix d.) what are (a) the magnitude (in knots) and (b) direction (measured relative to east) of the velocity of ship a relative to b? (c) after how many hours will the ships be 180 nautical miles apart? (d) what will be the bearing of b (the direction of the position of b) relative to a at that time? (for your angles, takes east to be the positive x-direction, and north of east to be a positive angle. the angles are measured from -180 degrees to 180 degrees. round your angles to the nearest degree.)

a) 38.8224 knots

b) 86° due north of east

c) 4.63 h

d) 86° due south of east

Explanation:

The velocity of B relative to A:

For the angle: It's on the first quadrant, so:

For the amount of time, we will use the relative velocity calculated:

The bearing of B relative to A will have the opposite direction of A relative to B, so:

α = -86°  This is 86° due south of east

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation:

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000