An object is thrown upward from the top of a 160 foot building with an initial velocity of 48 feet per second. the height h of the object after t seconds is given by the quadratic equation h= 16t2+48t+160. when will the object hit the ground?

Explanation:

From free falling objects we know that height is equal to:

From the exercise we know that

Being said that, we can calculate how long would it take to the object to hit the ground knowing that the height at that point is 0

Solving the quadratic formula we got that

or

Since time can not be negative the logical answer is t=5s

So, the object hit the ground at 5s

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14