Three moles of an ideal gas with a molar heat capacity at constant volume of 4.9 cal/(mol∙k) and a molar heat capacity at constant pressure of 6.9 cal/(mol∙k) starts at 300 k and is heated at constant pressure to 320 k, then cooled at constant volume to its original temperature. how much heat flows into the gas during this two-step process?

The heat flows into the gas during this two-step process is 120 cal.

Explanation:

Given that,

Number of moles = 3

Heat capacity at constant volume = 4.9 cal/mol.K

Heat capacity at constant pressure = 6.9 cal/mol.K

Initial temperature = 300 K

Final temperature = 320 K

We need to calculate the heat flow in to gas at constant pressure

Using formula of heat

Put the value into the formula

We need to calculate the heat flow in to gas at constant volume

Using formula of heat

Put the value into the formula

We need to calculate the heat flows into the gas during two steps

Using formula of total heat

Hence, The heat flows into the gas during this two-step process is 120 cal.

reserve is the answer