A1500 kg car traveling at 15 m/s to the south collides with a 4500 kg truck that is intially at rest at a spotlight. the car and the truck stick together and move together after the collison. what is the final velocity of the two-vehicle mass

The final velocity of the two-vehicle mass as they moved together after the collision is 3.75m/s

Given the data in the question;

Final or Combined velocity of the two-vehicle mass;

To determine final or combined velocity of the two-vehicle mass, we use Conservation of Momentum:

We substitute our given values into the equation

Therefore, the final velocity of the two-vehicle mass as they moved together after the collision is 3.75m/s.

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3.75 m/s south

Explanation:

Momentum before collision = momentum after collision

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

Since the car and truck stick together, v₁ = v₂.

m₁ u₁ + m₂ u₂ = (m₁ + m₂) v

Given m₁ = 1500 kg, u₁ = -15 m/s, m₂ = 4500 kg, and u₂ = 0 m/s:

(1500 kg) (-15 m/s) + (4500 kg) (0 m/s) = (1500 kg + 4500 kg) v

-22500 kg m/s = 6000 kg v

v = -3.75 m/s

The final velocity is 3.75 m/s to the south.

i need to show me the graph so i can give u an answer

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length