The speed of a bullet is 300. m/s as it emerges from the 1.00-meter-long barrel of a rifle. assume that the acceleration of the bullet is constant along the entire length of the barrel, and that the bullet started from rest. what is the acceleration, a, for the bullet while it is in the barrel? (hint: time doesn’t matter in this part. think about which kinematics equation to use.

45000 m/s^2

Explanation:

First, we know:

Bullet's Initial Velocity (Vo) = 0 m/s

Distance Travelled (D) = 1 m

Final Velocity (Vf) = 300 m/s

We need to know the bullets acceleration to reach the final velocity on that distance. Because the bullet stars from rest, his Initial Velocity is equal to zero.

We dont know on how much time it takes for the bullet, but we know the acceleration on the barrel is constant.

We can use the following equation for this

Because Vo is zero, the equation simplify, so we have.

Searching for the accelaration we obtain

Changing values

This is the acceleration needed to reach the velocity at the end of the barrel.

answer; (d) spontaneous processes are characterized by the overall conversion of order to disorder;

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .