Arifle can shoot a 4.20-g bullet at a speed of 965 m/s. a)find the ke of the bullet at this speed. b) what work is done on the bullet if it starts from rest? c) if thework is done over a distance of 0.75 m, what is the average force on the bullet? d) if the bullet comes to rest by pushing 1.5 cm into metal, what is the magnitude and direction of the average force the metal exerts?

a)  1955.6 J

b) 1955.6 J

c) 2607 N

d) 110373 J

Explanation:

a)

b) Work done on bullet should be increase in KE = 1955.6 J

c) Work done = Force \times displacement = KE of bullet

d) Work done to stop

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz