What change in volume results if 0.06 l of gas is cooled from 33.0 c to 5.00 c?

-0.005 L

Explanation:

Ideal gas law:

PV = nRT

where P is absolute pressure,

V is volume,

n is number of moles,

R is the gas constant,

and T is absolute temperature.

If P and n are held constant, then:

nR/P = nR/P

V/T = V/T

Given V₁ = 0.06 L, T₁ = 33.0 C = 306.15 K, and T₂ = 5.00 C = 278.15 K:

0.06 / 306.15 = V / 278.15

V = 0.055

The change in volume is:

0.055 L − 0.06 L = -0.005 L

the answer is the last option

explanation:

because in order to know what the molecule is you need to know how many atoms of each element are in the molecule.

the kind of relationship between atmospheric  density and altitude is inverse relationship. this means a surge in either will cut the other factor. density is mass per unit volume, it is hard to compute with only altitude 1,291 kilometers given. also, we could also use temperature and pressure to resolve density but they are not delivered.