Astubbor n, 120 kg mule sits down and refuses to move. to drag the mule to the ba rn, the exasperated far mer ties a rope around the mule and pulls with his maximum force of 800 n. the coef- ficients of friction between the mule and the g round are ms = 0.8 and mk = 0.5. is the farmer able to move the mule?

force exerted by the farmer is not enough to move the mule.

Explanation:

given,

mass of the mule = 120 Kg

force exerted by the farmer = 800 N

μ s(static friction coefficient) = 0.8

μ k (kinetic friction coefficient)= 0.5

frictional force on the mule when he is sitting

     F = π N                

here we will use static friction because mule is sitting

     F = π × m g                  

     F = 0.8 × 120 × 9.81            

    F = 941.76 N > 800 N                      

Hence, force exerted by the farmer is not enough to move the mule.

because growing process had stoped after 4-5 year

answer: 31, 5556. 952 seconds