Ahammer weighs 11 n on the surface of the earth. what is the weight of this hammer on the surface of a planet with a mass 3 x 10^18 kg and a radius of 4.21 x 10^4 m ?

The weight is 0.121 N

Explanation:

The weight (W) is defined by:

W=mg (I)

where m is the mass and g is the acceleration of gravity

You have to calculate the mass of the hammer and then the acceleration of gravity on the given planet, in order to calculate the weight of the hammer in that planet

Dividing (I) by g:

m=W/g

g on earth = 9.8 m/s²

Calculating the mass of the hammer:

m=11/9.8=1.1 kg

Now, you have to calculate the acceleration of gravity on the other planet, which is given by:

where G is the universal gravitational constant , M is the mass of the planet, and R is the radius of the planet.

Is known that G= 6.67 x N m²/kg²

Calculating the value of g:

g =

g= 0.11 m/s²

So the weight in that planet (Wp) is:

Wp=(1.1)(0.11) = 0.121 N

the pull of gravity on the rocket decreases

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: