Acar traveling 67 mph (30 m/s) accelerates for 3 seconds in order to reach a speed of 100 mph (45 m/s). a. what is the acceleration of the car in m/s^2
b. how far does it travel in m?

a. a = 5 m/s^2

b. distance traveled = 112.5 m

Explanation:

Acceleration is the rate of variation of the velocity of an object when it moves. If the object in question maintains its speed constantly, then it is not accelerating, something it will do when its speed changes. Acceleration is measured in meters per second squared, and it is based on the time it takes to move from one speed to another, or a force that is applied to the object.

In order to calculate it, it is essential that you know the acceleration formula (a = Δv / Δt). In it, "a" is the acceleration, "Δv" is the variation of the velocity and "Δt" is the time in that variation.

Calculation

a = Δv / Δt

a = (45 m/s - 30 m/s) / (3 s -0 s)

a = 5 m/s^2

To calculate the distance we need the average speed that he obtained in those 3 seconds

average speed: (45 m/s + 30 m/s) / 2 = 37.5 m/s

distance traveled = average speed * time

distance traveled = 37.5 m/s * 3 s

distance traveled = 112.5 m

its c its is a mixture of gases

the rearrangement of particles in a physical change. hope this