Asmall ball is attached to the lower end of a 0.800-m-long string, and the other end of the string is tied to a horizontal rod. the string makes a constant angle of 49.3° with the vertical as the ball moves at a constant speed in a horizontal circle. if it takes the ball 1.45 s to complete one revolution, what is the magnitude of the radial acceleration of the ball?

a= 11.36 m/s²

Explanation:

Radius of circle=R=0.8 sin∅

                             =0.8 sin(49.3)

                             =0.606 m

 and we know that

                               ω=

                                   =

                                 ω=4.33

                                 a=R ω²

                                   =0.606*(

                                  a=11.36 m/s²

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hope this