Aball is thrown straight down at 10.0 m/s from a 38.4 m-high building. how long does it take to reach the ground?

Ball will take 1.9591 sec to reach the ground        

Explanation:

We have given initial velocity of the ball u = 10 m/sec

Height from which ball is thrown h = 38.4 m

Acceleration due to gravity

From second equation of motion we know that

After solving equation for t

t= -4 sec and t = 1.9591 sec

As time can not be negative so time will be 1.9591 sec

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