Atoy rocket is launched with an initial ve- locity of 12.0 m> s in the horizontal direction from the roof of a 30.0-m-tall building. the rocket’s engine produces a horizontal acceleration of 11.60 m> s 3 2t, in the same direction as the initial velocity, but in the vertical direction the acceleration is g, down- ward. ignore air resistance. what horizontal distance does the rocket travel before reaching the ground?

D=90.3m.

Explanation:

Here we got a parabolic motion problem, On the Y axis we have a free-fall motion, so the time to reach the ground is given by:

Having that time we now can calculate the horizontal distance traveled by the rocket.

The acceleration is a continous function, if we integrate the acceleration we obtain the velocity:

the displacement is given by:

Substituting the time:

D=90.3 m

c) power lifting, will be your answer.

,

deku ❤