Ahorizontal circular turntable rotates about its center at the uniform rate of 10.9 revolutions per minutes. find the greatest distance (in meter) from the center at which a small block will remain stationary relative to the turn table. the coefficient of static friction between the turntable and the object is 0.8.

6.03 m

Explanation:

First of all, let's convert the angular velocity from revolutions per minute to radians per second:

The frictional force on the block ranges from zero to a maximum value of

In order for the block to remain stuck on the turntable, the frictional force must be equal to the centripetal force, so we can write:

where

m is the mass of the block

is the angular velocity

r is the distance of the block from the centre

is the coefficient of static friction

g = 9.8 m/s^2

Solving for r, we find:

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.