Adockworker applies a constant horizontal force of 72.0 n to a block of ice on a smooth horizontal floor. the frictional force is negligible. the block starts from rest and moves a distance 12.5 m in a time of 4.50 s . (a)what is the mass of the block of ice? (b)if the worker stops pushing at the end of 4.50 s, how far does the block move in the next 4.20s ?

58.54 kg

23.247 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

m = Mass

a) Equation of motion

Force

F = ma

Mass of block is 58.54 kg

b)

If this velocity is constant then

Distance = Speed × Time

Distance the block move in the next 4.20 s is 23.247 m

when earth is in rotational motion around the sun,it displaces from its place.

when a ball is placed on an inclined surface it does both the rotational and circular motion.

explanation:

i need the answer to this too but idk it ; -;