You place a box weighing 200.2 n on a inclined plane that makes a 37.1 angle with the horizontal. compute the component of the gravitational force acting down on the inclined plane. answer in units of n

141.56 N.

Explanation:

Data given:

Weight of the box= 200.2 N

Angle with the horizontal= 37.1°

Solution;

Gravitational force on the box, = weight of the box

                                                                           = 200.2 N

Component of gravitational force along plane = ( ∅ )

                                                                                   = W * (sin∅)

                                                                                   = (200.1) * sin (37.1°)

                                                                                   = 141.56 N

nah.   i'm just sleepy.

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle