6. the hole on a level, elevated golf green is a horizontal distance of 150 m from the tee and at an elevation of 12.4 m above the tee. a golfer hits a ball at an angle of 8.6° above the horizontal and makes a hole-in-one! what was the initial speed of the ball?

u = 104.68 m/s

Explanation:

given,

horizontal distance = 150 m

elevation of  12.4 m

angle = 8.6°

horizontal motion = x = u cos θ. t .............(1)

vertical motion =

................(2)

from equation(1) and (2)

..........{3}

u = 104.68 m/s

The initial speed of the ball is u = 104.68 m/s

nah.   i'm just sleepy.

0.19 m/s and 0.45 m/s