Aman pulls a wagon with a handle that is at an angle of 42° with the ground. if the man pulls with 330 n of force, how much force pulls the wagon forward?

245 n

220 n

330 n

110 n

245N

Explanation:

We just need to multiply the force the man pulls the wagon by the cosine of the angle with the ground.

F = 330N * cos(42°) = 245.2N

Answer :

The wagon is pulled by a force of 245.2377 N ~ 245 N, when the man pulls with 330 N of force at an angle of 42° with the ground.

Explanation :

The horse pulls the wagon at an angle of 42°. The angle is made along the horizontal parallel to ground surface.

On resolving the force (the pull) into its components, we get

= Horizontal force = 330 = 245.2377 N

= Vertical force = 330 = 220.813 N

For the Wagon to get pulled, we require (Horizontal force)

Therefore,

Force = = 245.2377 ~ 245 N

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s