A62kg person is going down the hill slopes at 32°. the coefficient of kinetic friction between the skis and the snow is 0.15. how fast is the skier going 5.0s after starting from rest

20. m/s

Explanation:

Draw a free body diagram of the skier.  There are three forces: normal force pushing perpendicular to the slope, weight pulling down, and friction force pushing up the slope.

Sum of the forces perpendicular to the slope:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces parallel to the slope:

∑F = ma

mg sin θ − Nμ = ma

Substituting:

mg sin θ − (mg cos θ) μ = ma

g (sin θ − μ cos θ) = a

Given g = 9.8 m/s², θ = 32°, and μ = 0.15:

a = (9.8 m/s²) (sin 32° − (0.15) cos 32°)

a = 3.95 m/s²

After 5.0 s, the velocity is:

v = at + v₀

v = (3.95 m/s²) (5.0 s) + (0 m/s)

v = 19.7 m/s

Rounded to two significant figures, the skier's velocity is 20. m/s.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz