An object is moving with an initial velocity of 23 m/s. it is then subject to a constant acceleration of 3.5 m/s2 for 12 s. how far will it have traveled during the time of its acceleration?

528 m

Explanation:

We can solve the problem by using the following suvat equation:

where

s is the displacement

u is the initial velocity

t is the time

a is the acceleration

In this problem,

u = 23 m/s

And substituting t = 12 s, we find the distance travelled:

it is called kinetic energy

multiply 2kg by latent heat of vap