An electron of mass 9.11 10-31 kg has an initial speed of 3.80 105 m/s. it travels in a straight line, and its speed increases to 7.60 105 m/s in a distance of 4.20 cm. assume its acceleration is constant. (a) determine the magnitude of the force exerted on the electron. 0.82875492 incorrect: your answer is incorrect. your response differs from the correct answer by more than 10%. double check your calculations. n (b) compare this force (f) with the weight of the electron (fg), which we ignored. f fg =

Explanation:

The acceleration experimented by the electron can be calculated using the formula , so we have:

The magnitude of of the force exerted on the electron can be then obtained using Newton's 2nd Law F=ma.

Putting all together we have:

And using our values (and that 4.2cm are 0.042m):

Then we compare this force with the weight of the electron:

So this force is 525702635794 times larger than the weight of the electron.

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the answer is c. the lower legs are levers, and the knees are fulcrums. the ankles hold the loads.