Gas at a pressure of 0.85 bar, volume 0.25m^3 and temperature 18°c, is compressed until the pressure is 2.8 bar and volume is 0.115m^3, calculate the compression index and the final temperature.

n=1.53

T₂ = 166.16 °C

Explanation:

Given that

P₁=0.85 bar

V₁= 0.25 m³

P₂=2.8 bar

V₂=0.115  m³

Lets take compression index is n

So

Now by putting the values

ln 3.29 = n ln 2.17

n=1.53

T₁=18°C=273+ 18 = 291 K

Lets final temperature =T₂

T₂=439.16 K

T₂ = 166.16 °C

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards