On question 1
i know the formula but i’m not getting the right answer

3870 m/s

Explanation:

V = (GM × 2π/T)^⅓

Given:

G = 6.67×10⁻¹¹ m³/kg/s²

M = 5.97×10²⁴ kg

T = 12.00 hr = 43,200 s

V = (6.67×10⁻¹¹ m³/kg/s² × 5.97×10²⁴ kg × 2π / 43,200 s)^⅓

V = 3870 m/s

the answer is to check all of them! they all apply well at least i think so!

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.