Afireworks shell is accelerated from rest to a velocity of 50.0 m/s over a distance of 0.240 m. (a) how long (in s) did the acceleration last? s (b) calculate the acceleration in m/s^2). (enter the magnitude.) /s^2

0.0096 seconds

5208.33 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The acceleration of the firework shell was 5208.33 m/s²

The acceleration lasted for 0.0096 seconds

(a) 0.0096 sec

(b)

Explanation:

We have given that firewall shell starts from rest so initial velocity u = 0 m/sec

And final velocity v = 50 m/sec

Distance s = 0.240 m

(A) From first equation pf motion we know that v = u+at

So 50 = 0+at

at = 50

Now from second equation of motion

Using the value of at = 50

(b) As at = 50

So

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.

d. air pressure decreases as altitude increases.