Physics, 18.10.2019 03:30 faithburleson13

A69.5-kg person throws a 0.0445-kg snowball forward with a ground speed of 35.0 m/s. a second person, with a mass of 56.5 kg, catches the snowball. both people are on skates. the first person is initially moving forward with a speed of 3.00 m/s, and the second person is initially at rest. what are the velocities of the two people after the snowball is exchanged? disregard the friction between the skates and the ice. (take the direction the snowball is thrown to be the positive direction. indicate the direction with the sign of your answer.)

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Answer from: ElmerRamirez

The velocity of the first person is 2.9795 m/s and the velocity of the second person is 0.0275 m/s

Explanation:

First, we are going to study the interacción between the ball and the first person. In every case the linear momentum is conserved so:

$m_1v_{i1} +m_bv_{ib}=m_1v_{f1}+m_bv_{b}$

Where m_1 is the mass of the first person, m_b is the mass of the ball, $v_{i1}$ and $v_{f1}$ are the initial and final velocities of the first person, $v_{ib}$ is the initial velocities of the ball and $v_{b}$ is the velocity of the ball once it is throws.

So, if we replace the values and solve for $v_{f1}$ , we get:

$69.5Kg(3m/s)+(0.0445Kg)(3m/s)=(69.5kg)v_{f1}+(0.0445)(35m/s)$

$208.6335=69.5v_{f1}+1.5575$

$\frac{208.6335-1.5575}{69.5}=v_{f1}\\2.9795=v_{f1}$

Therefore, the velocity of the first person after the snowball is exchanged is 2.9795 m/s

Now, we are going to study the interaction between the ball and the second person, we get:

$m_2v_{i2} +m_bv_{b}=m_2v_{f2}+m_bv_{fb}$

Where m_2 is the mass of the second person, $v_{i2}$ is the initial velocity of the second person, $v_{f2}$ is the final velocity of the second person and $v_{fb}$ is the final velocity of the ball.

$v_{f2}$ is equal to $v_{fb}$ , so if we replace the values and solve for $v_{f2}$ , we get:

$(56.5kg)(0 m/s)+(0.0445)(35)=(56.5Kg)v_{f2}+(0.0445Kg)v_{f2}$

$1.5575=(56.5445)v_{f2}$

$\frac{1.5575}{56.5445} =v_{f2}\\0.0275=v_{f2}$

Finally, the the velocity of the second person after the snowball is exchanged is 0.0275 m/s

Answer from: Quest

im guessing the west of station b

Answer from: Quest

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

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A69.5-kg person throws a 0.0445-kg snowball forward with a ground speed of 35.0 m/s. a second person...

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