A60 kg block slides along the top of a 100 kg block with an acceleration of 2.0 m/s2 when a horizontal force f of 340 n is applied. the 100 kg block sits on a horizontal frictionless surface, but there is friction between the two blocks.

The coefficient of friction and acceleration are 0.37 and 2.2 m/s²

Explanation:

Suppose we find the coefficient of friction and the acceleration of the 100 kg block during the time that the 60 kg block remains in contact.

Given that,

Mass of block = 60 kg

Acceleration = 2.0 m/s²

Mass = 100 kg

Horizontal force = 340 N

Let the frictional force be f.

We need to calculate the frictional force

Using balance equation

Put the value into the formula

We need to calculate the coefficient of friction

Using formula of friction force

We need to calculate the acceleration of the 100 kg block

Using formula of newton's law

Hence, The coefficient of friction and acceleration are 0.37 and 2.2 m/s²

the answer to this is proletariats.

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