Aman, located a distance d=3.0 m from a target, fires a projectile at an angle θ=70 ∘ above the horizontal. if the initial speed of the projectile is v=39.4 m/s, at what height hh does the projectile strike the building?

So at height of 139.874 m projectile will strike the building              

Explanation:

We have given that man is located at a distance of 3 m

Angle of projection

Initial velocity is given as

Height of projectile motion is given by

So

So at height of 139.874 m projectile will strike the building

it is b. absorbs thermal energy

490 n

f=125n a=2.5m/s2