Aproton (mass m = 1.67 × 10-27 kg) is being accelerated along a straight line at 2.50 × 1012 m/s2 in a machine. if the proton has an initial speed of 1.60 × 104 m/s and travels 3.90 cm, what then is (a) its speed
(b) the increase in its kinetic energy?

(A) Speed will be

(b) Change in kinetic energy =      

Explanation:

We have given mass of proton

Acceleration of the proton

Initial velocity u = m/sec

Distance traveled by proton s = 3.90 cm = 0.039 m

(a) From third equation of motion we know that

(b) Initial kinetic energy

Final kinetic energy

So change in kinetic energy

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