A1400 kg aircraft going 40 m/s collides with a 1500 kg aircraft that is parked and they stick together after the collision and are going 19.3 m/s after the collision. if they skid for 7 seconds before stopping, how far did they skid? hint: are the aircraft moving at a constant velocity after the collision or do they experience an acceleration?

67.6 m

Explanation:

For this problem, we just need to analyze the motion of the two planes after the collision.

The two planes stick together and move with a velocity of

u = 19.3 m/s

The problem tells us that they skid until they stop: so, their final velocity is

v = 0

Since the velocity is not constant, this means that they are accelerating.

We also know that they skid for a time of

t = 7 s

Therefore, we can find their stopping distance using the following suvat equation

And substituting, we find

answer: a ball

explanation: because it will bounce

the independent variable, or the one that is intentionally manipulated is the speed.