What mass of water is required to absorb 4.7 x 10^5 of energy from a car engine while the temperature was initially 25 what will be the new temperature

The mass of water required is, m = 1.492 Kg

The final temperature of water, = 100 °C

Explanation:

Given that

Energy absorbed by water, q = 4.5 x 10⁵ J

The initial temperature of water = 25 °C

The mass of water required to absorb the energy, m = ?

The final temperature of water, = ?

The formula for energy absorbed by the water,  

                                   q = m C ΔT   Joules

where,  

                                   C - specific heat capacity (4200 J/Kg °C)

                                    ΔT = - (change in temperature)

The maximum possible temperature of the water at Standard Temperature and Pressure is 100 °C

As the final temperature is not given, let us consider the maximum possible temperature of the water.

Therefore,  

                                    ΔT = -

                                           = 100 -25

                                           = 75 °C

To find the mass of water, from the above relation

                                        m = q/CΔT        Kg

Substituting the values in the above equation

                                        m = 4.5 x 10⁵/4200 x 75

                                        m = 1.492 Kg

Hence, the mass of water required is m = 1.492 Kg

prolly a beacuse the momentuem the car has increases while going down hill

the assestment will probley apele with cause and effect