Ablock of ice with mass 2 kg slides 0.750 m down an inclined plane that slopes downward at an angle of 36.9◦ below the horizontal. if the block of ice starts from rest, what is it’s final speed? you can ignore friction. work this problem two ways: with the work-energy theorem and using conservation of energy.

The final speed of the block is 2.97 m/s

Solution:

As per the question:

mass of the ice block, m = 2 kg

distance, d = 0.750 m

Angle,

Now,

We know that the work done can be given as the change in Kinetic energy of the block:

Since, the bock slides we have velocity in the downward direction only along the slope:

Now, the normal force is perpendicular to the displacement of the block, thus does not contribute to the work done, the only component of force that provides the work done is along the plane in the direction the block slides, thus:

Now, by work energy theorem:

Work done, W = Kinetic energy, KE

Thus

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.