Aprojectile is thrown with a wind. the wind produces a constant acceleration of 2 m/s/s in the same direction as the projectile’s horizontal direction. the projectile is launched with a velocity of 20 m/s at an angle of 30°. the projectile lands at the same height as it was launched. a. how far from the launch point does the projectile land? do this problem again with no numbers.

Explanation:

It is given that,

Initial speed of the projectile, u = 20 m/s

It is launched at an angle of 30 degrees . Let the projectile will land at a distance R from the launch point. It is called the range of the projectile. Mathematically, it is given by :

R = 35.34 meters

So, it will land at a distance of 35.34 meters from the launch point.

Let u is the speed with which the projectile is launched. The angle formed by the projectile is θ. The distance covered by the projectile form its launch point to the other point is called the range of the projectile. it is given by :

Hence, this is the required solution.

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.