Asteel ball rolls with constant velocity on a tabletop 1.95 m high. it rolls off and hits the ground 0.5 m away from the edge of the table. how fast was the ball rolling?

0.79 m/s

Explanation:

First of all, we analyze the vertical motion of the ball. It is a free fall motion, so its vertical displacement is given by

where

s = 1.95 m is the displacement

u = 0 is the initial vertical velocity

t is the time

is the acceleration of gravity

Solving for t, we find the time it takes for the ball to reach the ground:

Now we can analyze the horizontal motion: this is a uniform motion with constant speed, so the horizontal distance covered by the ball is

where

d = 0.5 m is the horizontal distance covered

t = 0.63 s is the time

Solving for vx, we find the horizontal velocity of the ball:

And this velocity is constant during the motion, so the ball was moving at 0.79 m/s when it rolls off the table.

vapour or gas assuming atmospheriv pressure

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