Asoccer player takes a cor- ner kick, lofting a stationary ball 35.0° above the horizon at 22.5 m/s. if the soccer ball has a mass of 0.425 kg and the player’s foot is in contact with it for 5.00 x 10-2 s, find (a) the x - and y - components of the soc- cer ball’s change in momentum and (b) the magnitude of the average force exerted by the player’s foot on the ball.

(a)

x=7.83 Kgm/s

y=5.48 Kgm/s

(b)

191.25 N

Explanation:

(a)

Change in momentum in x direction

where m is mass and v is the velocity and is the angle of kick  

Substituting m=0.425 Kg, v=22.5m/s and

Change in momentum in y direction

(b)

Force exerted by the player

F=mv/t where t is time

Substituting

F=(0.425*22.5)/0.05= 191.25 N

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

i will answer your question if you answer mine