Two blocks are connected by a very light string passing over a massless and frictionless pulley . traveling at constant speed, the 20.0 n block moves 75.0 cm to the right and the 12.0 n block moves 75.0 cm downward. (a) how much work is done on the 12.0 n block by (i) gravity and (ii) the tension in the string?

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s