Aforce of 1.150×103 n pushes a man on a bicycle forward. air resistance pushes against him with a force of 795 n. if he starts from rest and is on a level road, what speed will he be going after 35.0 m? the mass of the bicyclist and his bicycle is 90.0 kg.

He has a speed of 16.60m/s after 35.0 meters.

Explanation:

The final velocity can be determined by means of the equations for a Uniformly Accelerated Rectilinear Motion:

 (1)

The acceleration can be found by means of Newton's second law:

Where is the net force, m is the mass and a is the acceleration.

 (2)

All the forces can be easily represented in a free body diagram, as it is shown below.

Forces in the x axis:

 (3)

Forces in the y axis:

(4)

Solving for the forces in the x axis:

Where and :

Replacing in equation (2) it is gotten:

So the acceleration for the cyclist is , now that the acceleration is known, equation (1) can be used:

However, since he was originally at rest its initial velocity will be zero ().

He has a speed of 16.60m/s after 35.0 meters

an enlarged virtual image