Jason takes off from rest across level water on his jet-powered skis. the combined mass of jason and his skis is 75 kg (the mass of the fuel is negligible). the skis have a thrust of 200 n and a coefficient of kinetic friction on water of 0.10. unfortunately, the skis run out of fuel after only 17 s. how far has jason traveled when he finally coasts to a stop? a.) 250 mb.) 350 mc.) 490 md.) 660 m

Option D

660 m

Explanation:

ma=Thrust – friction where m is mass and a is acceleration

ma=200 - \mu mg

Substituting m for 75 kg, for 0.10, g for 9.81

75a=200 - 0.10*75*9.81

75a= 200-73.575

a=126.425/75

For the first 17 seconds

Velocity v = a*t = 1.685667 17 = 28.65633 m/s

Distance = = 243.5788 m

After fuel is over

Force acting is only friction

since m are common

Where v is final velocity which is zero because after running out of fuel, skis come to rest. U is initial velocity which is 28.65633 m/s

s = 418.5450765 m

Total distance = s1+s2 = 243.5788 m + 418.5450765 m m = 662.1239098 m

Distance covered is approximately 660 m

this means that the temperature of both substances will be equal