Zach, whose mass is 80 kg, is in an elevator descending at 10 m/s. the elevator takes 3.0s to brake to a stop at the first floor.
a. what is zach's apparent weight before the elevator startsbraking ?
b. what is zach's apparent wight while the elevator is braking?

784.8 Newton

1051.2 Newton

Explanation:

If the elevator is going down at a constant velocity then acceleration is zero and the apparent weight before braking is 784.8 N

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

While the elevator is braking it has acceleration -3.33 m/s².

The apparent weight of Zach would be 1051.2 Newton

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