Caculate the heat realeased as a 25.0 g gas sample condenses if the heat vaporation is 2000 j/g

The amount of heat required to change 25 grams of water into steam is 50,000 joules or 11,950 calories.

Explanation:

Heat of vaporization of water = 2000J/g = 478 cal/g

You can solve this problem using either joules or calories for heat.

Part I

Use the formula q = m·ΔHv

where

q = heat energy

m = mass

ΔHv = heat of vaporization

q = (25 g)x(2000J/g)

q = 50,000 J

Part II

q = m·ΔHf

q = (25 g)x( 478 cal/g)

q = 11,950 cal

Answer

The amount of heat required to change 25 grams of water into steam is 50,000 joules or 11,950 calories.

come closer and become far apart and become steam/gas

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