Using energy considerations, calculate the average force (in n) a 63.0 kg sprinter exerts backward on the track to accelerate from 2.00 to 8.50 m/s in a distance of 25.0 m, if he encounters a headwind that exerts an average force of 30.0 n against him.

115.995 N

Explanation:

a = (v^2 - u^2)/2s

= (8.5^2 - 2^2)/2(25)

= 1.365 m/s^2

F - 30 = ma

F = 30 + ma

= 30 + 63(1.365)

= 115.995 N

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