Afairground ride spins its occupants inside a flying saucer-shaped container. if the horizontal circular path the riders follow has an 8.00 m radius, (a) at what angular velocity (in rad/s) will the riders be subjected to a centripetal acceleration 1.5 times that due to gravity? 1.36 rad/s correct (100.0%) input 4 statusyou have completed this input. correct (100.0%) (b) how many revolutions per minute is this angular velocity equivalent to? 12.9 rpm correct (100.0%) input 5 statusyou have completed this input. correct (100.0%) (c) what is the magnitude of the centripetal force (in newtons) on a 48.0 kg rider?

a)

b)

c)

Explanation:

a) The angular velocity is related to the centripetal acceleration by the formula , which for our purposes we will write as:

Since we want this acceleration to be 1.5 times that due to gravity, for our values we will have:

b) 1 rpm (revolution per minute) is equivalent to an angle of radians in 60 seconds:

Which means we can use the conversion factor:

So we have (multiplying by the conversion factor, which is 1, not affecting anything but transforming our units):

c) The centripetal force will be given by Newton's 2nd Law F=ma, so on the centripetal direction for our values we have:

the reason is because the moon has some form of gravity, and that gravity pulls the ocean tides.

i believe the answer is a