Astudent measures the pressure, volume, and temperature of a gas in the laboratory and records the following data: p = 0.741 atm, v = 112 ml, t = 300 k based on this information, what would be the volume of the gas at stp? enter your answer to three significant figures in units of ml.

Explanation:

To solve this problem we will use the Ideal Gas Law, which forms the following formula

Where

= Pressure of Gas

= Volume of Gas

= Moles of Gas

= Constant = 0.0821 atm L/mol K

= Temperature of Gas

There are two states to consider

State 1 is given

= 0.741 atm

= 112 mL

= unknown

= 0.0821 atm L/mol K

= 300K

State 2 is based on Standard Room Temperature Pressure (STP) which are fixed values

= 1 atm

= unknown

= unknown

= 0.0821 atm L/mol K

= 273.15K

Since this is the same mass of gas it can be reasoned that the moles of gas are the same. We rearrange the Gas Law Formula to the following

We input the values and equate the formulas for both states by substituting the value of n

Answer

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.