Physics question-does anyone know how to do this with the working

taking the resistivity of platinoid as 3.3 x 10-7 m, find the resistance of 7.0 m of platinoid wire of average diameter 0.14 cm.

Resistance of wire, R = 1.5 ohm

Explanation:

Given that,

The resistivity of the platinoid wire, ρ = 3.3 x 10⁻⁷  ohm - meter

Length of the platinoid wire, l = 7 meter

Diameter of the wire, d = 0.14 cm  =  0.0014 m

Radius of the wire, r = d/2 = 7 x 10⁻⁴  m

Therefore, core sectional area of the wire, A = π r²

                                                                    = 1.539 x 10⁻⁶   m²

According to Pouillet's law, the resistance of a wire is given by the relation,

Substituting the values in the above equation

                       R = 3.3 x 10⁻⁷

                           = 1.5 ohm

Hence, the resistance of the given platinoid wire is,  R = 1.5 ohm      

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.