Agirl tosses a stone into the air with an initial upward velocity of 8.00 meters/second8.00 meters/second and hears the splash when it hits the water 4.20 seconds4.20 seconds later. how deep is the water level in the well below where she tossed the stone

Depth of well = 52.92 m

Explanation:

Consider the equation of motion s = ut + 0.5 at²

Take upward direction as positive,

            Initial velocity, u =   8 m/s

            Acceleration, a =   -9.81 m/s²

            Time, t = 4.20 s

Substituting

         s = ut + 0.5 at²

         s = 8 x 4.20 + 0.5 (-9.81) x 4.20²

         s = -52.92 m

So stone travels 52.92 m below the initial position.

Depth of well = 52.92 m

. west

no

sodium is solid at rt