6. a 7-kg bowling ball moving at 6.0 m/s strikes a 1-kg bowling pin. 11 we van
slows to 4.5 m/s in 0.05 s, how much force does it exert on the pin?
chanter 7. momentum

210 N

Explanation:

The change in momentum of the ball is equal (in magnitude) to the impulse given to the pin, according to

(1)

where

is the change in momentum of the ball

F is the force exerted on the pin

is the duration of the collision

For the bowling ball, we have

m = 7 kg (mass)

u = 6.0 m/s (initial velocity)

v = 4.5 m/s (final velocity)

So, the change in momentum (in magnitude) is

We also know the duration of the collision,

And so if we re-arrange eq.(1), we find the force exerted on the pin:

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.