Determine the required diameter of the pins at a and b if the allowable shear stress for the material is tallow = 100 mpa. both pins are subjected to double shear. a b c 2 kn/m 3 m prob. 1–81 1–82. the steel pipe is supported on the circular base plate and concrete pedestal. if the thickness of the pipe is t = 5 mm and the base plate has a radius of 150 mm, determine the factors of safety against failure of the steel and concrete. the applied force is 500 kn, and the normal failure stresses for steel and concrete are (sfail)st = 350 mpa and (sfail)con = 25 mpa, respectively. r t 100 mm 500 kn prob. 1–

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Newtons laws of motion