A1100 kg car moves along a horizontal road at speed v0 = 21.7 m/s. the road is wet, so the static friction coefficient between the tires and the road is only µs = 0.144 and the kinetic friction coefficient is even lower, µk = 0.1008. the acceleration of gravity is 9.8 m/s 2 . what is the shortest possible stopping distance for the car under such conditions? use g = 9.8 m/s 2 and neglect the reaction time of the driver. answer in units of m.

the shortest possible distance to stop is 238m

Explanation:

The car is moving at a constant velocity, so it's not accelerating, on the other side we have a friction force, this force is decelerating the car, so let's analyze it:

in this case, we need to use the kinetic friction coefficient because the car is moving:

The car is decelerating at

to obtain the distance we can use:

answer: question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation: