Asquare loop of wire surrounds a solenoid. the side of the square is 0.1 m, while the radius of the solenoid is 0.025 m. the square loop has a resistance of 30 w. the solenoid has 500 turns and is 0.3 m long. the current in the solenoid is increasing at a constant rate of 0.7 a/s. what is the current flowing in the square loop?

Explanation:

We first calculate the change in magnetic flux () due to the change in the magnitude of magnetic field (B), since que current (I) in the solenoid changes. B and are given by:

In this case, the magnetic field is always perpendicular to the square loop. We replace (2) in (1):

According to Faraday's law:

The minus sign means that the resulting current will have a direction such that the induced magnetic field will oppose the original change in flux. Here, n is the number of turns per unit length and A is the solenoid area

Recall that is an induced voltage. We use the Ohm's law to calculate the current:

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

true tan speed = ang vel x radius