Projectiles launched at an angle

in 1989 during overtime in a high school basketball game in erir, pennsylvania, chris eddy threw a basketball a distance of 27.5 m to score and win the game. if the shot was made at a 50° angle and reached a height of 9ft above the horizontal, what was the initial speed of the ball, the total time spend in the air, and the speed at which the ball was launched?

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Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.