A50-kg student stands on a scale in an elevator. at the instant the elevator has a downward acceleration of 1.0 m/s2 and an upward velocity of 3.0 m/s, the scale reads approximately(a) 350 n (b) 450 n (c) 500 n (d) 550 n (e) 650 n

Option D) 500 N is correct.

Given :

Mass = 50 Kg

Acceleration =  

Velocity = 3 m/sec

Solution :

F = ma            (from Newton's second law)

N - mg = ma

N = m(g - a)

N = 550 N

Therefore option D) 500 N is correct.

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D-550 N

Explanation:

Given

mass of student=50 kg

at particular instant elevator is moving downward with acceleration of  1 m/s^2

Net weight of man shown by scale will be more than his actual weight as elevator is decelerating

let N be the normal reaction on man thus

and Normal reaction will be shown by scale as apparent weight

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